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Capacitor Voltage-current Relations

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Here is our image when f=1kHz and A=2V Here is our image when F=2kHz and A=2v As the frequency is increased the voltage of the circuit changed signal faster.

Inductor Voltage-Current Relations

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For this lab we had a resistor and an inductor in series. We had to measure voltages for both elements and use this information to calculate the current running through inductor. The way we could see if our data was accurate was to use Ohm's law through the resistor. Since both elements are in series the would have the same current. For this lab we had a 1mH inductor a 17.6 ohm resistor. Here's a picture of our circuit Here's our graph window for a sinusoidal input voltage with frequency = 1kHz, amplitude = 2V, and offset = 0V Here's our graph window for a  sinusoidal input voltage with frequency = 2 kHz, amplitude = 2V, and offset = 0V Here's the inductor current we got from the wavegen generator and the one calculated from the pre-lab. Our values are pretty off, and I'm not exactly sure why, I'm assuming our math equation was wrong. Here's the graph When we had a frequency of 2khz we basically got the same graph, I'm assuming ...

Passive RL Circuit

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For this lab we had to connect a resistor parallel to an inductor and calculate the current and time constant of the inductor. Our R1 value was 100 ohms, our R2 was 47 ohms. Our inductor had a value of 1uH. We calculated that the inductor had a current of 0.05 amps at time zero, and 0 amps at time infinity. Our time constant was 0.031 us Leading to the equation       i(0)=0.05e^-t/(.031us) Here's a picture of the calculations  and circuit diagram                                                                                             Here are pictures of the oscilloscope this is a graph of the voltage through the resistors This is the graph for the current that we created using the values obtained from the r...

Passive RC Circuit Natural Response

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For this lab we had to estimate the initial capacitor voltage and the time constant . Here's the circuit diagram Here's a picture of the circuit    Our resistors were R1=.926K ~=1k R2=2.16~=2.2k Our capacitor =22 uF We calculated that our voltage  across the capacitor would be  3.44 V. Our actual voltage across the capacitor was 3.456 V. Our calculated time constant was 283 ms. Our actual value was 283. Here are pictures of the oscilloscope We were surprised at how close our values were. We assume the reason they weren't exact was due to the resistors, we were supposed to have exactly 2.2k and 1k but we had 2.16k and .926k. However besides this I think our values are pretty accurate. 

Difference Amp

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For this lab we had to create a difference amplifier, and find the relationship between vin and vout. From our calculations we found that if both the Rin resistors are the same values. The relationship between Vin and Vout is                                                   Vb-Va=Vout Where Vb and Va are our input voltages.  It's called a difference amplifier because it outputs the difference of the input voltages. Here's the circuit diagram Here's our circuit Here's our graphs This is for Vb=1 Our theoretical values didn't exactly match our experimental values. For example when Vb=1 and Va=-4 our Vout should've been 5, but we got 4.30. My reasoning for this, is because the resistors we used weren't exactly equal, so I'm assuming this created the difference between theory and experimen...

non-inverting amp

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The relationship for the non-inverting voltage amplifier was Vout=Vin*(  (R2/R1)+1) Our resistors values were 20k Ohms for the second resistor, but an actual resistance of 21.2k Ohm. For the first resistor the value is 10k Ohm, and the actual value is 9.95k Ohm. For the procedure, we increased the Vin voltage and wrote down the Vout voltage and created a graph. Here's the circuit diagram Here is our circuit Here are our values   We noticed that we reached saturation at -3.51 and 4.28 for the Vout. From our calculation we were supposed to have a gain of around 3. We only achieved this when our Vin went from -1.5 to 1.0 V. After that our values began to not match our theoretical gain. So from this we can deduce to achieve peak gain we need to stay between -1.5 and 1.0 volts.